s1779 7, Metoda elementu skończonego
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!" " " # " $""% &$" = ’(&) *+ " ", # ’ #- """) × .*+’)% = × = 0 / 1& . ’(.) 2 " # ’(.) ! - """ = - & × ’(3) 3"4 = × - & × = 4 × ’(5) % 4 = × - & ’(6) 7(8, 9: & . 1;& 1& 4 & = & ’ - x ) . 4 . = & ’ + x ) . 7(&< " 5 6 # = # $ > ? ’ )"" @""" ’") "" "## ## ;& $"" " " " 4 (& & . $ " !#A"B ;&<B CD&>"""% A = & ’ - x ) A + & ’ + x ) A ’(6) . & . . # . A = = 4 A ’(:) & 4 & 1 =6’&;B) 4 . 1 =6’&DB) , " " ’" ) ! ! " ’(6) " " !- A B @# !# # 7(8, 9( . = = 4 ’(() & " " ’" ) " ! E- "% ; F1GA2% e = x ’(9) x A H"2I-% I = & 0 - & & / ’(J) H % ; " " " K"""!! " MN + - & - & = × 0 - & & × L × x ’(&=) H & & ""#!-# ! " A = L × x ’(&&) L1HG. "% MN & & - & = - ’(&.) H - & & & L-! ## ;& $ - ! 6 . 7(8, 99 (& L !" " !"> ! #- "; ; # " ! $ ! # " $!""#" " -!% O O O A = = 4 A = = 4 = = 4 ’(&3) & & & A A ’1& O) "?"B P Q " ;& D& 4 ’(&3) " " 4 ?" ! - "" !""-&E*+ -*=+ $"! 3’(.) & . 3 A1= A1=3H A1H 1;& 1& & 1;& 1= 1& & & 4 = & - x . . 4 = & ’ - x ) - & ’ - x . ) & . . 4 = & ’ + x ) - & ’ - x . ) 3 . . 7(.>"" 7(8, 9J ! !"#-"# ?"4 . -"" ## %B1R&"= B1= & - 4 . 1 ’&;B . ) $ " " " " # 4 4 & " ’&;B)G. % B 1 ;& " & B1& = I - ! B 1 = 4 & " = " " # ;’&;B . )G. # " "4 & 1=6S’&;B);=6S’&;B . )$#"4 3 $ !" " ! # - " ! " ! - ! ’(&3) " ! - # # " # ! #2""- "" !!% O O O = = 4 T = = 4 T = = 4 ’(&5) & & & # " ! # $! ’(&5) E- A B P Q!-"% A = & ’ x h z ) = . ’ x h z ) = 3 ’ x h z ) ’(&6) #"!% x = & ’ A ) h = . ’ A ) z = 3 ’ A ) ’(&:) N# - " # " "- UGUA UGUUGU"!"!" % d = d dx + d dh + d dz ’(&() d A dx d A dh d A dz d A #!-!UGUUGU#UBGUA [ Pobierz całość w formacie PDF ] |